How do I solve this?
Aside from my final in two weeks, today hopefully marks the last effing math test I'll ever have to take. Here's a homework problem I can't solve:
1. A group of 30 people is selected at random. What is the probability that at least two of them will have the same birthday?
I think this is kind of how it's supposed to be setup:
n(E') = 365P3 = 365!/(365-30)!
That's as far as I can get. Most calculators can't solve such high numbers.
The answer in the back says: 0.71
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