Quote:
Originally posted by drolldurham
what's the limit of the function
f(x)=
X^2-5x+6
------------------
x-3
(that's a fraction, by the way)
(and "X^2" is X squared)
...as x approaches 3?
t(^-^)
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Hmm let's see.. You could make that
(x-3)(x-2)
------------
x-3
X-3 cancels out which leaves you with
x-2 when x is approaching 3
Which means the limit is 1.