Thread: Ok Any Math Wise Help
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Old 03-05-2002, 11:37 AM   #15
ed328
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Quote:
Originally posted by BreakABone
Well if anyone cares to work it out..

The answer is 128pi/3
That is the answer if y=PI*(16-x²).

But y=sqrt(16-x²) which does not equal PI*(16-x²).

What exactly are the conditions that you have to use your formula PI*integral of [R(x)]²dx? From the information you've given us, Xantar and I are correct.
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